READ THE SAMPLE AND INSTRUCTIONS PAGE before uploading!

REMINDER: Please name your files 2P2XX FILENAME before uploading in case you overwrite other peoples' files!

DAY 1: 25 May

Type a 100-word reflection for today's lesson.

After today's elearning session, I have learnt the formulas for finding length/distance between 2 points and how to find the mid-point. I feel that this would be essential in mathematics when we learn more in depth. So, we have to build a good foundation of mathematics. I also like the style of learning at home as I feel less stressed however, in this way, I will not be able to meet up with my friends. Everything has its own benefits and disadvantages. To conclude, I would like to say that I have grasped the gist of the topic that is taught today.

DAY 2: 26 May

After this engaging elearning session, I feel that creating a good image on TI-83+ is not easy at all. It requires time and patience. Of course, we will also need a good foundation in this topic. Through the creation of the Olympic Ring image, I realised that actually creating a full circle requires 2 equations, one being + and one being -, as the one of the side would be the top and the other would be the bottom. This topic is really interesting and challenging. For Design 3(Syringe), it is more complex than Design 1(London 2010). I feel that my images are more of being an oval than a circle and I am trying to fix the problem.

Equations:
(Circle)
Y1 = 3 + {[squareroot](2.5^2-(x-3.5)^2)}
Y2 = 3 - {[squareroot](2.5^2-(x-3.5)^2)}
(Longer Line)
Y3 = ((11-2x)/1)/
(x is more than or equal to 3
and x is less than or equal to 4.5)
(Shorter Line)
Y4 = ((2x-4)/1)/
(x is more than or equal to 3
and x is less than or equal to 3.75)

READ THE SAMPLE AND INSTRUCTIONS PAGE before uploading!

REMINDER: Please name your files

2P2XX FILENAMEbefore uploading in case you overwrite other peoples' files!DAY 1: 25 May

Type a 100-word reflection for today's lesson.After today's elearning session, I have learnt the formulas for finding length/distance between 2 points and how to find the mid-point. I feel that this would be essential in mathematics when we learn more in depth. So, we have to build a good foundation of mathematics. I also like the style of learning at home as I feel less stressed however, in this way, I will not be able to meet up with my friends. Everything has its own benefits and disadvantages. To conclude, I would like to say that I have grasped the gist of the topic that is taught today.

DAY 2: 26 May

After this engaging elearning session, I feel that creating a good image on TI-83+ is not easy at all. It requires time and patience. Of course, we will also need a good foundation in this topic. Through the creation of the Olympic Ring image, I realised that actually creating a full circle requires 2 equations, one being + and one being -, as the one of the side would be the top and the other would be the bottom. This topic is really interesting and challenging. For Design 3(Syringe), it is more complex than Design 1(London 2010). I feel that my images are more of being an oval than a circle and I am trying to fix the problem.Submission of Designs:Design 1(LONDON 2010)Design 2("RU4")Design 3(SYRINGE)Design 4 (Optional)(BOAT)Window Settings:

Xmin = 0

Xmax = 7

Ymin = 0

Ymax = 7

Equations:

Blue Ring

Y1 = 5 + {[squareroot](1-(x-1.5)^2)}

Y2 = 5 - {[squareroot](1-(x-1.5)^2)}

Black Ring

Y3 = 5 + {[squareroot](1-(x-3.5)^2)}

Y4 = 5 - {[squareroot](1-(x-3.5)^2)}

Red Ring

Y5 = 5 + {[squareroot](1-(x-5.5)^2)}

Y6 = 5 - {[squareroot](1-(x-5.5)^2)}

Yellow Ring

Y7 = 4 + {[squareroot](1-(x-2.5)^2)}

Y8 = 4 - {[squareroot](1-(x-2.5)^2)}

Green Ring

Y9 = 4 + {[squareroot](1-(x-4.5)^2)}

Y10 = 4 - {[squareroot](1-(x-4.5)^2)}

Window Settings:

Xmin = 0

Xmax = 6

Ymin = 0

Ymax = 6

Equations:

(Circle)

Y1 = 3 + {[squareroot](2.5^2-(x-3.5)^2)}

Y2 = 3 - {[squareroot](2.5^2-(x-3.5)^2)}

(Longer Line)

Y3 = ((11-2x)/1)/

(x is more than or equal to 3

and x is less than or equal to 4.5)

(Shorter Line)

Y4 = ((2x-4)/1)/

(x is more than or equal to 3

and x is less than or equal to 3.75)

this design.