READ THE SAMPLE AND INSTRUCTIONS PAGE before uploading!

REMINDER: Please name your files 2P2XX FILENAME before uploading in case you overwrite other peoples' files!

DAY 1: 25 May

Type a 100-word reflection for today's lesson.

Today, I learn about how to combine Pythagoras Therom with cartesian coordinate to find the distance between 2 points, after viewing the video
I felt that the video was rather successful in telling me the equation for finding the distance between 2 points. I also learn how to find midpoint between 2 points. Before I viewed the video, I thought it was very hard, but after viewing the video, I found out that it was actually rather easy.

I wish to ask some questions, though. If the distance between 2 points equation can tell us the perimeter of the triangle, can we use it to find the area of the triangle through PythagorasTherom?

Not so easy, unless it's a right-angled triangle in the first place. You will encounter a problem in finding the height of the triangle. WIthout drawing out the triangle, it won't be so straightforward. In Sec 3, you will learn a formula to calculate the area of a shape from the coordinates of its vertices. It's called the shoelace formula - perhaps you want to google? :)

DAY 2: 26 May

Type a 100-word reflection for today's lesson and comment on your work.

Today, I learn the important equation (x-a)(y-b)=r. I think this formula is rather useful in solving circle questions. I think this formula can be used together with Pythagoras therom to find the line tangent to the edge of the circle. (need to click the edit button to view my design)

Submission of Designs:

Design 2 ("RU4")

Design 3 (SYRINGE)

Design 3 (Optional) (BOAT)

x min = -20
x max= 15
y min = -10
y max = 10

circle 1: 2+sqrt(16-(x+8)^2)
circle 2: 2-sqrt(16-(x+8)^2)
circle 3: 2+sqrt(16-x^2)
circle 4: 2+sqrt(16-x^2)
circle 5: 2+sqrt(16-(x-8)^2)
circle 6: 2-sqrt(16-(x-8)^2)
circle 7: -2+sqrt(16-(x+5)^2)
circle 8: -2+sqrt(16-(x+5)^2)

x min = -9
x max = 9
y min =-9
y max = 9

inner circle y1= 0+sqrt(49-x^2)
inner circle y2= 0- sqrt(49-x^2)
outer circle y3= 0+sqrt(64-x^2)
outer circle y4= 0-sqrt(64-x^2)
1st stroke y5= -3x+2/x>=-1.5 and x=<3
1st stroke y6= -3x+3/x>=-1 and x=<3
2nd stroke y7=3x+2/x>=-3 and x=<0
2nd stroke y8=3x+3/x>=-3 and x=<0

READ THE SAMPLE AND INSTRUCTIONS PAGE before uploading!

REMINDER: Please name your files

2P2XX FILENAMEbefore uploading in case you overwrite other peoples' files!DAY 1: 25 May

Type a 100-word reflection for today's lesson.

Today, I learn about how to combine Pythagoras Therom with cartesian coordinate to find the distance between 2 points, after viewing the video

I felt that the video was rather successful in telling me the equation for finding the

distance between 2 points. I also learn how to find midpoint between 2 points. Before I viewed the video, I thought it was very hard, but after viewing the video, I found out that it was actually rather easy.

I wish to ask some questions, though. If the

distance between 2 points equation can tell us the perimeter of the triangle, can we use it to find the area of the triangle through PythagorasTherom?Not so easy, unless it's a right-angled triangle in the first place. You will encounter a problem in finding the height of the triangle. WIthout drawing out the triangle, it won't be so straightforward. In Sec 3, you will learn a formula to calculate the area of a shape from the coordinates of its vertices. It's called the shoelace formula - perhaps you want to google? :)

DAY 2: 26 May

Type a 100-word reflection for today's lesson and comment on your work.Today, I learn the important equation (x-a)(y-b)=r. I think this formula is rather useful in solving circle questions. I think this formula can be used together with Pythagoras therom to find the line tangent to the edge of the circle. (need to click the edit button to view my design)

Submission of Designs:Design 2("RU4")Design 3(SYRINGE)Design 3 (Optional)(BOAT)x max= 15

y min = -10

y max = 10

circle 1: 2+sqrt(16-(x+8)^2)

circle 2: 2-sqrt(16-(x+8)^2)

circle 3: 2+sqrt(16-x^2)

circle 4: 2+sqrt(16-x^2)

circle 5: 2+sqrt(16-(x-8)^2)

circle 6: 2-sqrt(16-(x-8)^2)

circle 7: -2+sqrt(16-(x+5)^2)

circle 8: -2+sqrt(16-(x+5)^2)

x max = 9

y min =-9

y max = 9

inner circle y1= 0+sqrt(49-x^2)

inner circle y2= 0- sqrt(49-x^2)

outer circle y3= 0+sqrt(64-x^2)

outer circle y4= 0-sqrt(64-x^2)

1st stroke y5= -3x+2/x>=-1.5 and x=<3

1st stroke y6= -3x+3/x>=-1 and x=<3

2nd stroke y7=3x+2/x>=-3 and x=<0

2nd stroke y8=3x+3/x>=-3 and x=<0