Lionell Loh...

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DAY 1: 25 May

I feel that today's lesson is fairly simple and easy to understand. It consists of the formula of Pythagorus Theorem. From today's lesson, I now know how to find the distance of 2 points by have their coordinates. (And also the mid points) Other than that, I manage to see the usefulness of Pythagorus Theorem and I am sure that these topics we have just learnt will be very useful in future. I also felt that the videos and powerpoint chosen were quite appropriate and managed to help me understand the topic very easily. However, my work speed was not fast when solving the questions, I will strive to do work faster in the future.

DAY 2: 26 May

Today's lesson is quite challenging. Again, I am amazed by how the use of Pythagorus Theorem can find out so many things. I also feel that the lessons plans are very precise and well planned for us as I figured out that it is sort of leading us one step by one step and eventually, we managed to learn the equation of circles. However, the seem to be a big gap between the step where we find out the equation of the radius and why the need of 2 equations for each circle. That aspect was not properly explained in my opinion, later did I discover that each equation is for each curves, while both curves will make a circle.
I felt quite satisfied after being able to finish the design. Although I did some referring, I made a point to understand the concept.


Submission of Designs:
Design 1
(LONDON 2010)

Design 2
("RU4")

Design 3
(SYRINGE)

Design 3 (Optional)
(BOAT)
2P219_LionellLoh_GC_Design_1.PNG
Window settings
Xmin = -10
Xmax= 30
Xsc1 =1
Ymin=-10
Ymax=10
Ysc1=1
Xres=1

Ring 1

Y1 =5+Sqrt(25-(X+5)^2)
Y2 =
5-Sqrt(25-(X+5)^2)
Ring 2
Y3 =Sqrt(25-(X)^2)
Y4 =-Sqrt(25-(X)^2)

Ring 3
Y5 =5+Sqrt(25-(X-5)^2)
Y6 =
5-Sqrt(25-(X-5)^2)
Ring 4
Y7 =Sqrt(25-(X-10)^2)
Y8 =-Sqrt(25-(X-10)^2)

Ring 5
Y9 =5+Sqrt(25-(X-15)^2)
Y10 = 5-Sqrt(25-(X-15)^2